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WSupported on Windows
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USupported on Unix
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VSupported on OpenVMS
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NSupported in Synergy .NET
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xcall L_PLACE(list_id, [row][, column])
Arguments
list_id
The ID of the list to place. (n)
row
(optional) The row position for the list. (n)
column
(optional) The column position for the list. (n)
Discussion
L_PLACE places a list. After you have placed the list, if you remove it at a subsequent environment level, the list will automatically be placed again when you call E_EXIT to exit that later environment.
If row and/or column is not passed, the default position is the previous row and/or column placement position. If no previous position exists, the list will be placed at the row and/or column position that was specified when the list was created.
See also
L_REMOVE routine for information on removing a list
Examples
The following example moves the list, whose ID is stored in order_lst, vertically to row 5. The horizontal position will be the same as the previous placement , if it’s valid, or the original placement.
xcall l_place(order_lst, 5)
The next example removes the list whose ID is stored in trans_lst, and then processes the menu. If the user selects the menu entry whose name is “PRCTRNS,” the list will be placed at its previous location.
xcall l_remove(trans_lst) xcall m_process case g_entnam of begincase . . . "PRCTRNS": begin ;Place the list at xcall l_place(trans_lst) ; previous position call process ;Process the list end endcase
