FOR-UNTIL-DO
Repeatedly execute a statement (alternate)
WTSupported in traditional Synergy on Windows
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WNSupported in Synergy .NET on Windows
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USupported on UNIX
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VSupported on OpenVMS
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FOR var = initial[ STEP incr] UNTIL final DO statement
Arguments
var
A variable that controls the repeated execution of the statement. (n)
initial
An expression whose value is initially assigned to var. (n)
incr
(optional) An expression whose result is added to var after each repetition of the statement, with the exception of the first repetition. The default value is 1. (n)
final
An expression for the terminating value, which is compared against the current value of var at the beginning of each repetition of the statement. (n)
statement
A single or compound statement to be repeatedly executed.
Discussion
The FOR-UNTIL-DO statement executes a statement repeatedly as long as the control value is within a specified range.
If the entering incr is positive, statement is executed while var is less than or equal to final. If the entering incr is negative, statement is executed while var is greater than or equal to final.
Incr and final are evaluated prior to each execution of statement.
Statement must execute code; for example, it cannot contain only a label.
The difference between FOR-UNTIL-DO and FOR-FROM-THRU is that FOR-UNTIL-DO can modify the final and incr values, while FOR-FROM-THRU cannot.
The FOR and the DO keywords must always be on the same line. |
Examples
The following example assigns the values 65, 72, 79, and 86 to the elements of result. The first value is the initial value 65. Each of the remaining values is equal to the immediately preceding value plus 7. Only four values are assigned because v4 is assigned a value of 93 (86 + 7), which is greater than the final value of 91 before the fifth repetition.
record v1 ,d3, 13 v2 ,d3, 5 v3 ,d3, 7 v4 ,d3 i ,d3, 1 result ,d4 proc for v4 = v1 * v2 step v3 until v1 * v3 do begin result(i) = v4 incr i end end
The following example assigns the values 20.2, 13.8, 7.4, and 1.0 to the first four elements of result.
record idval ,d3.1 i ,d2, 1 idresult ,10d3.1 proc for idval = 20.2 step -6.4 until 0.0 do begin idresult(i) = idval incr i end end